m^2+3m+2.25=0

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Solution for m^2+3m+2.25=0 equation: 



m^2+3m+2.25=0

a = 1; b = 3; c = +2.25;
Δ = b2-4ac
Δ = 32-4·1·2.25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{-3}{2}=-1+1/2$

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